Worked example
An ideal cone 18 ft across and 6 ft high contains about 509 ft³, or 18.85 yd³. At an illustrative 2,800 lb/yd³ bulk density, that would weigh about 26.39 US short tons.
Geometry comes before density
The cone equation uses one-third of base area times height. OpenStax gives the right-circular-cone formula. Divide cubic feet by 27 to get cubic yards. Diameter must be the full width of the base, not its radius.
A real pile can depart from a cone
A flattened top, irregular footprint, sidewall or multiple peaks make this idealized shape inaccurate. Measure the actual footprint and profile for inventory or contract work. The calculator does not add a hidden compaction or swell factor.
Weight needs the matching bulk density
If entered, density is multiplied by the estimated yardage and divided by 2,000 pounds per US short ton. Use a supplier or measured density for that same material state. An empty density field leaves weight uncalculated rather than guessing from a material name.
Explore the related calculation
For a different starting point, try the bulk-density guide or return to the main calculator. Browse the complete tool directory for this site.
Reference and corrections
The definitions and assumptions above follow these sources; the examples and calculator arithmetic are original to this page.
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